Test Statistic Calculator N Y S
This test statistic calculator helps you compute the n y s test statistic, which is commonly used in statistical hypothesis testing. Understanding this value is essential for making informed decisions based on your data.
What is a Test Statistic?
A test statistic is a standardized value calculated from sample data to determine whether there is enough evidence to reject the null hypothesis in a hypothesis test. The n y s test statistic is specifically used when comparing sample means to a population mean.
Test statistics help quantify the difference between observed data and what would be expected under the null hypothesis. A higher absolute value of the test statistic suggests stronger evidence against the null hypothesis.
How to Calculate Test Statistic n y s
The formula for calculating the n y s test statistic is:
n y s = (x̄ - μ) / (σ/√n)
Where:
- x̄ = sample mean
- μ = population mean
- σ = population standard deviation
- n = sample size
This formula standardizes the difference between the sample mean and population mean by the standard error of the mean. The result is a z-score that can be compared to critical values from the standard normal distribution.
Note: This calculator assumes you know the population standard deviation. If you only have sample standard deviation, use the t-distribution instead.
Interpreting the Results
The test statistic n y s follows a standard normal distribution when the null hypothesis is true. You can use this to make decisions about your hypothesis test:
- If |n y s| > critical value (from z-table), reject the null hypothesis
- If |n y s| ≤ critical value, fail to reject the null hypothesis
The p-value associated with the test statistic gives the probability of observing a result as extreme as yours if the null hypothesis were true. Smaller p-values provide stronger evidence against the null hypothesis.
Worked Example
Let's calculate the test statistic for a sample with:
- Sample mean (x̄) = 75
- Population mean (μ) = 70
- Population standard deviation (σ) = 10
- Sample size (n) = 36
Using the formula:
n y s = (75 - 70) / (10/√36) = 5 / (10/6) = 5 / 1.6667 ≈ 3.00
This result suggests strong evidence against the null hypothesis if we're using a 5% significance level (critical value ≈ 1.96).