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If Y N 5 10 Calculate Pr Xy 0

Reviewed by Calculator Editorial Team

This guide explains how to calculate the probability that the product XY equals zero when Y follows a normal distribution N(5,10). We'll cover the formula, assumptions, practical applications, and common questions.

Introduction

When working with random variables, especially those following normal distributions, calculating probabilities involving products can be challenging. This guide focuses on determining PR(XY=0) when Y ~ N(5,10).

The key insight is that the product XY equals zero if either X equals zero or Y equals zero. Since we're given the distribution of Y, we need to consider the distribution of X to complete the calculation.

Formula

The probability that XY equals zero can be expressed as:

PR(XY=0) = PR(X=0) + PR(Y=0) - PR(X=0 AND Y=0)

This formula accounts for the cases where either X or Y is zero, using the principle of inclusion-exclusion to avoid double-counting the scenario where both are zero.

Calculation

Given Y ~ N(5,10), we know:

  • Mean (μ) = 5
  • Variance (σ²) = 10
  • Standard deviation (σ) = √10 ≈ 3.162

The probability that Y equals zero is the probability that a normally distributed random variable equals exactly zero. For a continuous distribution like the normal distribution, the probability of any exact value is zero. Therefore:

PR(Y=0) = 0

This means the second term in our formula is zero. The calculation simplifies to:

PR(XY=0) = PR(X=0)

This result makes intuitive sense: since Y cannot equal zero in a continuous distribution, the only way XY can equal zero is if X equals zero.

Interpretation

The result PR(XY=0) = PR(X=0) means that the probability that the product XY equals zero is equal to the probability that X equals zero. This is a fundamental property of continuous random variables in probability theory.

Note: This result holds specifically for continuous distributions. For discrete distributions, the calculation would differ.

In practical terms, this means that if you're working with a system where one component (Y) follows a normal distribution and the other component (X) can be zero, the probability that the product is zero depends entirely on the probability that X is zero.

FAQ

Why is PR(Y=0) equal to zero for a normal distribution?
For continuous distributions like the normal distribution, the probability of any exact value is zero because there are infinitely many possible values. This is a fundamental property of continuous probability distributions.
What if X also follows a normal distribution?
If both X and Y follow normal distributions, then PR(X=0) and PR(Y=0) would both be zero, making PR(XY=0) = 0. This is because the probability that any single normally distributed random variable equals exactly zero is zero.
Can this formula be used for other distributions?
Yes, the inclusion-exclusion principle can be applied to other distributions, but the specific probabilities would depend on the characteristics of those distributions. For example, with discrete distributions, exact values can have non-zero probabilities.
What are practical applications of this calculation?
This type of calculation is useful in reliability engineering, where components can fail (X=0) or operate normally. The probability that the system fails (XY=0) depends on the individual failure probabilities of the components.