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Evaluate Integral Using U Substitution Calculator

Reviewed by Calculator Editorial Team

U-substitution (also called integration by substitution) is a technique for evaluating integrals that involve composite functions. This method is particularly useful when the integrand is a product of a function and its derivative. Our calculator helps you solve integrals using this method step-by-step.

What is U-Substitution?

U-substitution is a method of integration that involves reversing the chain rule. The chain rule states that if you have a composite function, the derivative is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function.

If \( y = f(g(x)) \), then \( \frac{dy}{dx} = f'(g(x)) \cdot g'(x) \).

In integration, we reverse this process. If we have an integral that resembles the derivative of a composite function, we can use u-substitution to simplify it.

How to Use U-Substitution

To use u-substitution, follow these steps:

  1. Identify the inner function \( u \) in the integrand.
  2. Find the derivative of \( u \) with respect to \( x \), which is \( du/dx \).
  3. Express \( dx \) in terms of \( du \) using \( dx = du/(du/dx) \).
  4. Rewrite the integral in terms of \( u \).
  5. Integrate with respect to \( u \).
  6. Substitute back to the original variable \( x \).

Remember that the substitution must be reversible. If you can't solve for \( x \) in terms of \( u \), the substitution may not be valid.

Example Problems

Let's look at an example to see how u-substitution works in practice.

Example 1: Simple Polynomial

Evaluate \( \int x(2x + 3)^5 \, dx \).

Solution:

  1. Let \( u = 2x + 3 \).
  2. Then \( du = 2 \, dx \) or \( dx = du/2 \).
  3. Substitute into the integral: \( \int x \cdot u^5 \cdot \frac{du}{2} = \frac{1}{2} \int x u^5 \, du \).
  4. Notice that \( x \) is not expressed in terms of \( u \). We need to solve for \( x \) in terms of \( u \): \( x = \frac{u - 3}{2} \).
  5. Substitute back: \( \frac{1}{2} \int \frac{u - 3}{2} u^5 \, du = \frac{1}{4} \int (u^6 - 3u^5) \, du \).
  6. Integrate: \( \frac{1}{4} \left( \frac{u^7}{7} - \frac{3u^6}{6} \right) + C = \frac{u^7}{28} - \frac{u^6}{8} + C \).
  7. Substitute back to \( x \): \( \frac{(2x + 3)^7}{28} - \frac{(2x + 3)^6}{8} + C \).

Common Mistakes

When using u-substitution, it's easy to make a few common mistakes:

  • Forgetting to multiply by \( du/dx \) when substituting back.
  • Choosing the wrong substitution. The substitution should simplify the integral, not complicate it.
  • Not checking if the substitution is reversible.
  • Making algebraic errors when solving for \( x \) in terms of \( u \).

Frequently Asked Questions

What is the difference between u-substitution and integration by parts?

U-substitution is used when the integrand is a composite function, while integration by parts is used when the integrand is a product of two functions. Both methods are based on reversing differentiation rules.

When should I use u-substitution instead of other integration techniques?

Use u-substitution when the integrand contains a composite function and the derivative of the inner function appears elsewhere in the integrand. If the integrand is a product of two functions, consider integration by parts.

Can u-substitution be used for definite integrals?

Yes, u-substitution can be used for definite integrals. After performing the substitution, you'll need to change the limits of integration accordingly.