Cal11 calculator

Describe The Following Sequence. -2 6 -18 54 ....calculator

Reviewed by Calculator Editorial Team

This guide explains how to analyze and extend the sequence -2, 6, -18, 54... using our calculator and step-by-step explanation.

Identifying the Pattern

The sequence -2, 6, -18, 54... appears to follow a pattern where each term is multiplied by a certain factor to get the next term. Let's examine the relationships between consecutive terms:

  • From -2 to 6: Multiply by -3 (6 ÷ -2 = -3)
  • From 6 to -18: Multiply by -3 (-18 ÷ 6 = -3)
  • From -18 to 54: Multiply by -3 (54 ÷ -18 = -3)

This suggests a geometric sequence where each term is multiplied by -3 to get the next term.

The Formula

The general formula for a geometric sequence is:

aₙ = a₁ × r^(n-1)

Where:

  • aₙ = nth term
  • a₁ = first term (-2 in this sequence)
  • r = common ratio (-3 in this sequence)
  • n = term number

For our sequence:

aₙ = -2 × (-3)^(n-1)

Extending the Sequence

Using the formula, we can find the next terms in the sequence:

Term (n) Calculation Value
1 -2 × (-3)^0 -2
2 -2 × (-3)^1 6
3 -2 × (-3)^2 -18
4 -2 × (-3)^3 54
5 -2 × (-3)^4 -162
6 -2 × (-3)^5 486

The extended sequence is: -2, 6, -18, 54, -162, 486...

Common Mistakes

When analyzing sequences, it's easy to make these common errors:

  • Assuming an arithmetic pattern when it's geometric
  • Incorrectly identifying the common ratio
  • Miscounting the term positions (n)
  • Forgetting to account for negative signs in calculations

FAQ

Is this sequence arithmetic or geometric?

This is a geometric sequence because each term is multiplied by a constant ratio (-3) to get the next term.

How do I find the 10th term of this sequence?

Use the formula aₙ = -2 × (-3)^(n-1) with n = 10. The 10th term would be -2 × (-3)^9 = -2 × 19683 = -39366.

Can this sequence be extended infinitely?

Yes, the sequence can be extended infinitely by continuing to multiply each term by -3.