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Calculate The Voltage of The Following Cell Zn Zn2+

Reviewed by Calculator Editorial Team

This calculator helps you determine the voltage of a Zn/Zn²⁺ electrochemical cell using the Nernst equation. The calculation takes into account the standard reduction potential of zinc and the activity of the zinc ions in solution.

Introduction

The Zn/Zn²⁺ cell is a simple electrochemical cell where zinc metal is oxidized to zinc ions (Zn²⁺) and electrons are released. The voltage of this cell can be calculated using the Nernst equation, which relates the reduction potential of a reaction to the activities or concentrations of the species involved.

Understanding the voltage of this cell is important in electrochemistry, battery technology, and corrosion science. The Nernst equation provides a way to predict the voltage based on the standard reduction potential and the concentration of the zinc ions in solution.

Nernst Equation Formula

The Nernst equation is given by:

E = E° - (RT/nF) * ln(Q)

Where:

  • E = cell potential (V)
  • E° = standard reduction potential (V)
  • R = gas constant (8.314 J/mol·K)
  • T = temperature (K)
  • n = number of electrons transferred
  • F = Faraday constant (96,485 C/mol)
  • Q = reaction quotient

For the Zn/Zn²⁺ cell, the standard reduction potential (E°) is 0.763 V at 25°C. The reaction quotient (Q) is equal to the concentration of Zn²⁺ ions.

How to Calculate Cell Voltage

To calculate the voltage of the Zn/Zn²⁺ cell:

  1. Determine the standard reduction potential (E°) of the cell, which is 0.763 V at 25°C.
  2. Measure or estimate the concentration of Zn²⁺ ions in the solution.
  3. Use the Nernst equation to calculate the cell potential (E).

Note: The Nernst equation assumes ideal conditions and may not account for all real-world factors such as temperature variations, ion interactions, and electrode kinetics.

Worked Examples

Example 1: Standard Conditions

At standard conditions (1 M Zn²⁺, 25°C):

E = 0.763 V - (8.314 J/mol·K * 298 K / 2 * 96,485 C/mol) * ln(1)

E = 0.763 V - 0.0296 V * 0

E = 0.763 V

Example 2: Diluted Solution

For a 0.01 M Zn²⁺ solution at 25°C:

E = 0.763 V - (8.314 J/mol·K * 298 K / 2 * 96,485 C/mol) * ln(0.01)

E = 0.763 V - 0.0296 V * (-4.605)

E ≈ 0.763 V + 0.137 V

E ≈ 0.899 V

Frequently Asked Questions

What is the standard reduction potential of the Zn/Zn²⁺ cell?

The standard reduction potential of the Zn/Zn²⁺ cell is 0.763 V at 25°C.

How does the concentration of Zn²⁺ ions affect the cell voltage?

As the concentration of Zn²⁺ ions increases, the cell voltage decreases. This is because higher concentrations of Zn²⁺ ions favor the reduction of Zn²⁺ to Zn, reducing the cell voltage.

What is the Nernst equation used for?

The Nernst equation is used to calculate the reduction potential of a half-cell or the cell potential of an electrochemical cell under non-standard conditions.