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Calculate The Standard Entropy of The Following Reaction at 25

Reviewed by Calculator Editorial Team

Calculating the standard entropy of a chemical reaction at 25°C is essential for understanding the spontaneity and energy changes in thermodynamic processes. This guide explains how to perform the calculation, interpret the results, and use the information in practical applications.

How to Calculate Standard Entropy

The standard entropy of a reaction (ΔS°) is calculated using the standard entropies of the products and reactants. The formula accounts for the entropy change of the system and the surroundings.

Key Concept

Standard entropy (S°) is a measure of disorder or randomness in a system at standard conditions (25°C and 1 atm pressure). For reactions, we calculate the change in entropy (ΔS°) to determine if the reaction is spontaneous.

Steps to Calculate

  1. Identify the balanced chemical equation for the reaction.
  2. Look up the standard entropy values (S°) for each reactant and product in J/(mol·K).
  3. Multiply each standard entropy by the stoichiometric coefficient from the balanced equation.
  4. Sum the entropies of the products and subtract the sum of the entropies of the reactants to get ΔS°.

The Formula

Standard Entropy of Reaction Formula

ΔS° = Σ(n·S°products) - Σ(m·S°reactants)

Where:

  • ΔS° = Standard entropy change of the reaction (J/(mol·K))
  • n, m = Stoichiometric coefficients of the products and reactants
  • S° = Standard entropy of each species (J/(mol·K))

The units for standard entropy are joules per mole per kelvin (J/(mol·K)). The calculation assumes standard conditions of 25°C (298.15 K) and 1 atm pressure.

Worked Example

Let's calculate the standard entropy of the reaction:

2H2(g) + O2(g) → 2H2O(l)

Step 1: Look Up Standard Entropies

Species State S° (J/(mol·K))
H2(g) Gas 130.7
O2(g) Gas 205.1
H2O(l) Liquid 69.9

Step 2: Apply the Formula

ΔS° = [2 × (69.9 J/(mol·K))] - [2 × (130.7 J/(mol·K)) + 1 × (205.1 J/(mol·K))]

ΔS° = 139.8 - (261.4 + 205.1)

ΔS° = 139.8 - 466.5

ΔS° = -326.7 J/(mol·K)

Result Interpretation

The negative value indicates that the reaction leads to a decrease in entropy, meaning the system becomes more ordered. This aligns with the formation of liquid water from gases, which is a common exothermic reaction.

Interpreting the Results

The standard entropy of a reaction provides insights into the spontaneity and energy changes:

  • Positive ΔS°: The reaction increases disorder (e.g., gas formation).
  • Negative ΔS°: The reaction decreases disorder (e.g., liquid or solid formation).
  • Zero ΔS°: The reaction maintains the same disorder (e.g., phase changes at constant temperature).

Combining ΔS° with the standard enthalpy change (ΔH°) helps determine if a reaction is spontaneous (ΔG° = ΔH° - TΔS°).

FAQ

What is standard entropy?
Standard entropy (S°) is a measure of the disorder or randomness of a system at standard conditions (25°C and 1 atm pressure).
How do I find standard entropy values?
Standard entropy values can be found in chemistry reference books, online databases like NIST, or thermodynamic tables.
What are the units for standard entropy?
Standard entropy is measured in joules per mole per kelvin (J/(mol·K)).
Can standard entropy be negative?
Yes, a negative standard entropy indicates a decrease in disorder, which often occurs in reactions forming liquids or solids.
How does standard entropy relate to spontaneity?
Standard entropy is used with standard enthalpy to calculate the Gibbs free energy change (ΔG°), which determines if a reaction is spontaneous.