Cal11 calculator

Calculate The Ph of A 0.20 M Solution of Nh4br

Reviewed by Calculator Editorial Team

This calculator helps you determine the pH of a 0.20 M solution of ammonium bromide (NH4Br). The pH of a solution is a measure of its acidity or basicity, and understanding how to calculate it is essential in chemistry and related fields.

Introduction

The pH of a solution is a logarithmic measure of the concentration of hydrogen ions (H⁺) in the solution. It is calculated using the formula:

pH = -log₁₀[H⁺]

For a solution of NH4Br, which is a salt of a weak base (NH3) and a strong acid (HBr), the pH can be determined using the following steps:

  1. Calculate the concentration of NH3 (the conjugate base of NH4⁺).
  2. Use the Ka value of NH3 to find the equilibrium concentration of NH3.
  3. Calculate the pH from the equilibrium concentration of NH3.

How to Calculate the pH

Step 1: Understand the Dissociation

NH4Br dissociates in water according to the following reaction:

NH4Br → NH3 + HBr

NH3 is a weak base with a dissociation constant (Ka) of 1.8 × 10⁻⁵. The HBr is a strong acid that completely dissociates in water.

Step 2: Set Up the Equilibrium Equation

The equilibrium equation for NH3 is:

NH3 + H2O ⇌ NH4⁺ + OH⁻

The Ka expression for this reaction is:

Ka = [NH4⁺][OH⁻]/[NH3]

Step 3: Calculate the Equilibrium Concentrations

For a 0.20 M solution of NH4Br, the initial concentration of NH3 is 0.20 M (since NH4Br dissociates completely into NH3 and HBr).

Let x be the equilibrium concentration of NH3 that dissociates. At equilibrium:

[NH3] = 0.20 - x [NH4⁺] = x [OH⁻] = x

Substituting into the Ka expression:

1.8 × 10⁻⁵ = (x)(x)/(0.20 - x)

Solving this quadratic equation gives the value of x.

Step 4: Calculate the pH

Once x is known, the pH can be calculated using the concentration of OH⁻:

pOH = -log₁₀[OH⁻] pH = 14 - pOH

Example Calculation

Let's calculate the pH of a 0.20 M solution of NH4Br step by step.

Step 1: Assume Initial Concentrations

Initial [NH3] = 0.20 M

Step 2: Solve the Ka Equation

1.8 × 10⁻⁵ = x² / (0.20 - x)

Solving this equation gives x ≈ 0.00134 M.

Step 3: Calculate [OH⁻]

[OH⁻] = x ≈ 0.00134 M

Step 4: Calculate pOH and pH

pOH = -log₁₀(0.00134) ≈ 2.87 pH = 14 - 2.87 ≈ 11.13

The calculated pH of a 0.20 M solution of NH4Br is approximately 11.13.

Interpreting the Results

A pH of 11.13 indicates that the solution is basic. This is expected because NH4Br dissociates to form NH3, which is a weak base.

The pH increases as the concentration of NH4Br increases because more NH3 is available to dissociate and form OH⁻ ions.

Practical Implications

Understanding the pH of NH4Br solutions is important in various chemical processes, including buffer preparation and pH control in laboratory settings.

FAQ

What is the pH of a 0.20 M solution of NH4Br?

The pH of a 0.20 M solution of NH4Br is approximately 11.13.

Why is NH4Br a basic solution?

NH4Br dissociates to form NH3, which is a weak base. The dissociation of NH3 produces OH⁻ ions, making the solution basic.

How does the concentration of NH4Br affect the pH?

Increasing the concentration of NH4Br increases the amount of NH3 available for dissociation, which raises the pH.

What is the Ka value of NH3?

The Ka value of NH3 is 1.8 × 10⁻⁵.