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Calculate The Iterated Integral U-V

Reviewed by Calculator Editorial Team

This guide explains how to calculate iterated integrals of the form ∫∫(u-v) dx dy. We'll cover the process, provide a calculator, and include examples to help you understand and solve these integrals.

What is an iterated integral?

An iterated integral is a sequence of integrals where the result of one integral becomes the integrand of the next. For two variables, this is written as ∫∫f(x,y) dx dy, which means we first integrate with respect to x, then with respect to y.

The integral ∫∫(u-v) dx dy represents the double integral of the function u-v over a region in the xy-plane. This is commonly encountered in physics and engineering when dealing with area calculations or probability distributions.

Calculating ∫∫(u-v) dx dy

To calculate ∫∫(u-v) dx dy, follow these steps:

  1. Identify the limits of integration for both x and y
  2. First integrate (u-v) with respect to x, treating y as a constant
  3. Then integrate the result with respect to y
  4. Evaluate the definite integral using the given limits

Formula

∫∫(u-v) dx dy = ∫[∫(u-v) dx] dy

Where u and v are functions of x and y

Note: The order of integration matters. If you integrate with respect to y first, the result may differ from integrating x first.

Example calculation

Let's calculate ∫∫(x²y - 2xy) dx dy over the region where 0 ≤ x ≤ 1 and 0 ≤ y ≤ 2.

Step 1: Integrate with respect to x

First, integrate (x²y - 2xy) with respect to x from 0 to 1:

∫(x²y - 2xy) dx = [x³y/3 - x²y] evaluated from 0 to 1

= (1³y/3 - 1²y) - (0³y/3 - 0²y) = (y/3 - y) - 0 = -2y/3

Step 2: Integrate with respect to y

Now integrate the result -2y/3 with respect to y from 0 to 2:

∫(-2y/3) dy = [-y²/3] evaluated from 0 to 2

= (-4/3) - 0 = -4/3

Final Result

The value of ∫∫(x²y - 2xy) dx dy over the given region is -4/3.

Common pitfalls

  • Forgetting to change the order of integration when the limits are not simple
  • Miscounting the number of integrals needed for the problem
  • Incorrectly evaluating the definite integral at the limits
  • Assuming symmetry when the integrand is not symmetric

FAQ

What is the difference between single and iterated integrals?

A single integral calculates the area under a curve, while an iterated integral calculates the volume under a surface over a region in 2D space.

When would I use an iterated integral instead of a single integral?

You would use an iterated integral when you need to calculate quantities that depend on two variables, such as probability densities or physical quantities in 3D space.

Can I change the order of integration?

Yes, but you must adjust the limits of integration accordingly. The order can be changed if the region of integration is simple and the limits are not mixed.