Calculate The Following in 7.87 G Li3po4
This calculator helps you determine the molar mass, number of moles, and other properties of lithium phosphate (Li3PO4) when given a mass of 7.87 grams. Understanding these calculations is essential for chemistry students and professionals working with lithium phosphate compounds.
Introduction
Lithium phosphate (Li3PO4) is an inorganic compound commonly used in various industrial and chemical applications. Calculating its properties from a given mass is fundamental in chemistry. This guide explains how to calculate the molar mass, number of moles, and other related properties of Li3PO4 when you have 7.87 grams of the compound.
Formula
The key formula for these calculations is the molar mass of Li3PO4. The molar mass is calculated by summing the atomic masses of all atoms in the compound:
Molar mass of Li3PO4 = (3 × Atomic mass of Li) + (1 × Atomic mass of P) + (4 × Atomic mass of O)
Where:
- Atomic mass of Li = 6.941 g/mol
- Atomic mass of P = 30.974 g/mol
- Atomic mass of O = 15.999 g/mol
Once you have the molar mass, you can calculate the number of moles using the formula:
Number of moles = Mass / Molar mass
Calculation
Let's calculate the properties of 7.87 g of Li3PO4:
- Calculate the molar mass of Li3PO4:
Molar mass = (3 × 6.941) + (1 × 30.974) + (4 × 15.999)
= 20.823 + 30.974 + 63.996
= 115.793 g/mol
- Calculate the number of moles:
Number of moles = 7.87 g / 115.793 g/mol
= 0.0679 moles
Example
Let's work through an example to see how this calculation applies in a real-world scenario.
Example Scenario
You have a 7.87 g sample of lithium phosphate. You need to determine how many moles of Li3PO4 are present in this sample.
- First, calculate the molar mass of Li3PO4 as shown above (115.793 g/mol).
- Then, divide the mass of your sample by the molar mass to find the number of moles.
- For 7.87 g of Li3PO4, you would find 0.0679 moles.