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Calculate The Equilibrium Constant at 25 Degrees for Co2

Reviewed by Calculator Editorial Team

The equilibrium constant (K) for a chemical reaction is a fundamental concept in chemistry that quantifies the position of equilibrium at a given temperature. For CO2 at 25°C (298.15 K), we can calculate the equilibrium constant using the van't Hoff equation and standard thermodynamic data.

What is the equilibrium constant?

The equilibrium constant (K) is a measure of the ratio of product concentrations to reactant concentrations at equilibrium for a given reaction. For the dissociation of CO2:

CO₂(g) ⇌ CO(g) + ½ O₂(g)

The equilibrium constant expression is:

K = [CO][O₂]^(1/2) / [CO₂]

Where square brackets denote concentrations. The value of K depends on temperature and the standard Gibbs free energy change of the reaction.

How to calculate the equilibrium constant

To calculate the equilibrium constant at 25°C (298.15 K) for CO2 dissociation, we use the following steps:

  1. Obtain the standard Gibbs free energy change (ΔG°) for the reaction at 25°C
  2. Use the relationship between ΔG° and K: ΔG° = -RT ln K
  3. Solve for K by rearranging the equation

The standard Gibbs free energy change for the CO2 dissociation reaction at 25°C is approximately -170.5 kJ/mol.

ΔG° = -RT ln K

Where R is the gas constant (8.314 J/mol·K) and T is temperature in Kelvin (298.15 K)

Example calculation

Let's calculate the equilibrium constant for the CO2 dissociation reaction at 25°C using the standard Gibbs free energy change of -170.5 kJ/mol.

  1. Convert ΔG° to joules: -170.5 kJ/mol = -170,500 J/mol
  2. Plug values into the equation: -170,500 = -8.314 × 298.15 × ln K
  3. Solve for ln K: ln K = 170,500 / (8.314 × 298.15) ≈ 7.35
  4. Calculate K: K = e^7.35 ≈ 1,600

Therefore, the equilibrium constant for CO2 dissociation at 25°C is approximately 1,600.

Note: This calculation assumes ideal gas behavior and standard conditions. Real-world conditions may affect the actual equilibrium constant.

Interpreting the results

A K value of 1,600 indicates that at equilibrium, the product concentrations ([CO] and [O₂]) are 1,600 times greater than the reactant concentration ([CO₂]). This suggests that the reaction strongly favors the formation of CO and O₂ from CO₂ at 25°C.

The equilibrium constant is temperature-dependent. As temperature increases, K typically increases for endothermic reactions and decreases for exothermic reactions. For CO2 dissociation, which is endothermic, K would increase at higher temperatures.

FAQ

What units are used for the equilibrium constant?
The equilibrium constant has no units because it's a ratio of concentrations or pressures.
How does temperature affect the equilibrium constant?
The equilibrium constant is temperature-dependent. The van't Hoff equation relates changes in K to changes in temperature.
What is the difference between Kp and Kc?
Kp uses partial pressures, while Kc uses concentrations. They are related by the reaction stoichiometry and the ideal gas law.
Can the equilibrium constant be negative?
No, the equilibrium constant is always positive. Negative values would imply that the reaction would proceed in the reverse direction, which contradicts the definition of equilibrium.