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Calculate The E Cell for The Following Equation 2fe2+

Reviewed by Calculator Editorial Team

Calculating the cell potential (E cell) for a redox reaction involves determining the difference in standard electrode potentials and adjusting for concentration effects using the Nernst equation. This guide explains how to calculate the E cell for the equation 2Fe²⁺ → 2Fe³⁺ + 2e⁻.

How to Calculate the E cell

The cell potential (E cell) is calculated using the standard electrode potentials (E°) of the half-reactions involved. For the equation 2Fe²⁺ → 2Fe³⁺ + 2e⁻, we need the standard reduction potential for Fe³⁺/Fe²⁺.

Formula: E°cell = E°cathode - E°anode

For the given equation, Fe³⁺/Fe²⁺ is the cathode (reduction) and Fe²⁺/Fe is the anode (oxidation).

Once you have the standard potentials, you can calculate the actual cell potential using the Nernst equation, which accounts for concentration differences.

Standard Electrode Potentials

Standard electrode potentials (E°) are measured under standard conditions (1 M concentration, 25°C, 1 atm pressure). For the equation 2Fe²⁺ → 2Fe³⁺ + 2e⁻, the relevant half-reactions are:

  • Cathode (reduction): Fe³⁺ + e⁻ → Fe²⁺ (E° = +0.77 V)
  • Anode (oxidation): Fe²⁺ → Fe³⁺ + e⁻ (E° = -0.77 V)

Note: The standard potential for Fe³⁺/Fe²⁺ is +0.77 V. The oxidation half-reaction has the same magnitude but opposite sign.

The Nernst Equation

The Nernst equation calculates the actual cell potential (E cell) based on standard potential and concentration differences:

Nernst Equation: Ecell = E°cell - (RT/nF) * ln(Q)

Where:

  • E°cell = standard cell potential
  • R = gas constant (8.314 J/mol·K)
  • T = temperature in Kelvin
  • n = number of electrons transferred
  • F = Faraday constant (96,485 C/mol)
  • Q = reaction quotient

For the given equation, n = 2 (since 2 electrons are transferred).

Example Calculation

Let's calculate the E cell for the equation 2Fe²⁺ → 2Fe³⁺ + 2e⁻ with the following conditions:

  • Initial [Fe²⁺] = 1 M
  • Initial [Fe³⁺] = 0 M
  • Final [Fe²⁺] = 0.1 M
  • Final [Fe³⁺] = 0.9 M
  • Temperature = 25°C (298 K)

Step 1: Calculate E°cell = E°cathode - E°anode = 0.77 V - (-0.77 V) = 1.54 V

Step 2: Calculate Q = [Fe³⁺]/[Fe²⁺] = 0.9/0.1 = 9

Step 3: Plug into Nernst equation:

Ecell = 1.54 V - (0.0257 V) * ln(9) ≈ 1.54 V - 0.063 V ≈ 1.48 V

The calculated E cell is approximately 1.48 V under these conditions.

FAQ

What is the standard potential for Fe³⁺/Fe²⁺?
The standard reduction potential for Fe³⁺/Fe²⁺ is +0.77 V. The oxidation half-reaction has the same magnitude but opposite sign.
How does concentration affect the E cell?
Concentration differences are accounted for using the Nernst equation, which adjusts the standard potential based on the reaction quotient (Q).
What is the Nernst equation used for?
The Nernst equation calculates the actual cell potential (E cell) by accounting for standard potential and concentration differences.
Can I calculate E cell without knowing concentrations?
Yes, you can calculate the standard cell potential (E°cell) using standard electrode potentials, but actual cell potential requires concentration data.
What units are used for standard electrode potentials?
Standard electrode potentials are measured in volts (V) under standard conditions (1 M concentration, 25°C, 1 atm pressure).