Calculate The Boiling Point of Each of The Following Solutions
Determining the boiling point of solutions is essential in chemistry and chemical engineering. The boiling point elevation formula allows you to calculate how much a solvent's boiling point increases when a solute is added. This guide explains the formula, provides a calculator, and includes practical examples.
Introduction
The boiling point of a solution is higher than that of the pure solvent due to the presence of solute particles. This phenomenon is known as boiling point elevation. The increase in boiling point depends on the concentration of the solute and the solvent's properties.
Key factors affecting boiling point elevation include:
- The number of solute particles dissolved in the solvent
- The nature of the solute-solvent interactions
- The temperature of the solution
Understanding boiling point elevation is crucial for processes like distillation, where precise temperature control is necessary.
Boiling Point Elevation Formula
The boiling point elevation (ΔTb) can be calculated using the following formula:
ΔTb = i × Kb × m
Where:
- ΔTb = Boiling point elevation (in °C)
- i = Van't Hoff factor (dimensionless)
- Kb = Ebullioscopic constant (in °C·kg/mol)
- m = Molality of the solution (in mol/kg)
The Van't Hoff factor accounts for the number of particles a solute dissociates into. For example, NaCl dissociates into 2 ions, so i = 2.
The ebullioscopic constant (Kb) is specific to each solvent. For water, Kb is approximately 0.512 °C·kg/mol.
How to Calculate Boiling Points
Step-by-Step Calculation Process
- Determine the molality (m) of the solution using the formula: m = moles of solute / kg of solvent
- Identify the Van't Hoff factor (i) based on the solute's dissociation behavior
- Find the ebullioscopic constant (Kb) for the solvent
- Plug these values into the boiling point elevation formula
- Calculate the boiling point elevation (ΔTb)
- Add ΔTb to the pure solvent's boiling point to get the solution's boiling point
Note: The boiling point of the pure solvent is typically 100°C for water at standard conditions.
Worked Examples
Example 1: Sodium Chloride in Water
Calculate the boiling point of a solution containing 25 g of NaCl in 250 g of water.
- Calculate moles of NaCl: 25 g / 58.44 g/mol ≈ 0.428 mol
- Calculate molality: 0.428 mol / 0.250 kg ≈ 1.712 mol/kg
- Van't Hoff factor (i) for NaCl = 2
- Ebullioscopic constant (Kb) for water = 0.512 °C·kg/mol
- ΔTb = 2 × 0.512 × 1.712 ≈ 1.74 °C
- Boiling point = 100°C + 1.74°C = 101.74°C
Example 2: Sucrose in Water
Calculate the boiling point of a solution containing 50 g of sucrose in 500 g of water.
- Calculate moles of sucrose: 50 g / 342.3 g/mol ≈ 0.146 mol
- Calculate molality: 0.146 mol / 0.500 kg ≈ 0.292 mol/kg
- Van't Hoff factor (i) for sucrose = 1 (does not dissociate)
- Ebullioscopic constant (Kb) for water = 0.512 °C·kg/mol
- ΔTb = 1 × 0.512 × 0.292 ≈ 0.15 °C
- Boiling point = 100°C + 0.15°C = 100.15°C