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Calculate P 69 X 71 When N 25

Reviewed by Calculator Editorial Team

This calculator helps you determine the probability of exactly 69 successes in 71 independent trials when the probability of success on each trial is 25%. The calculation uses the binomial probability formula, which is commonly used in statistics and probability theory.

What is P 69 x 71?

P 69 x 71 represents the probability of getting exactly 69 successes in 71 independent trials, where each trial has a probability of success equal to 25%. This is a specific case of binomial probability, which is used in various fields including quality control, medical testing, and sports analytics.

The notation "P 69 x 71" can be interpreted as the probability of 69 successes (x) in 71 trials (n), with the probability of success on each trial (p) being 25% or 0.25.

How to Calculate P 69 x 71

To calculate the probability of exactly 69 successes in 71 trials, you can use the binomial probability formula. Here are the steps:

  1. Identify the number of trials (n), which is 71 in this case.
  2. Determine the number of successes (x), which is 69.
  3. Find the probability of success on each trial (p), which is 25% or 0.25.
  4. Calculate the probability of failure on each trial (q), which is 1 - p = 0.75.
  5. Compute the combination of n items taken x at a time, which is C(n, x) or "n choose x".
  6. Multiply the combination by p raised to the power of x and q raised to the power of (n - x).

The result is the probability of getting exactly 69 successes in 71 trials.

Binomial Probability Formula

Formula

P(x; n, p) = C(n, x) × px × (1-p)n-x

Where:

  • P(x; n, p) = Probability of exactly x successes in n trials
  • C(n, x) = Combination of n items taken x at a time
  • p = Probability of success on an individual trial
  • n = Number of trials
  • x = Number of observed successes

The combination C(n, x) can be calculated using the formula:

Combination Formula

C(n, x) = n! / (x! × (n - x)!)

Where "!" denotes factorial, which is the product of all positive integers up to that number.

Example Calculation

Let's calculate P(69; 71, 0.25) step by step:

  1. First, calculate the combination C(71, 69):
  2. C(71, 69) = 71! / (69! × (71-69)!) = 71! / (69! × 2!) = 2551

  3. Next, calculate px and (1-p)n-x:
  4. 0.2569 ≈ 1.23 × 10-15

    0.752 = 0.5625

  5. Multiply these values together with the combination:
  6. P(69; 71, 0.25) = 2551 × 1.23 × 10-15 × 0.5625 ≈ 1.79 × 10-11

Therefore, the probability of exactly 69 successes in 71 trials with a 25% chance of success on each trial is approximately 1.79 × 10-11 or 0.0000000000179.

Interpretation

The result of 1.79 × 10-11 means that there is approximately a 0.0000000000179 probability of getting exactly 69 successes in 71 trials when each trial has a 25% chance of success.

This is an extremely low probability, indicating that getting exactly 69 successes in 71 trials with a 25% success rate is highly unlikely. In practical terms, this result might be useful in scenarios where you're analyzing the performance of a system or process with a known failure rate.

Note

The actual probability may vary slightly due to rounding in intermediate calculations. For precise results, use a calculator with higher precision or programming tools.

FAQ

What is the difference between P 69 x 71 and P ≥ 69 x 71?

P 69 x 71 represents the probability of exactly 69 successes, while P ≥ 69 x 71 represents the probability of 69 or more successes. The latter includes probabilities for 69, 70, and 71 successes.

Can I use this calculator for other values of n, x, and p?

Yes, you can use this calculator for any values of n, x, and p by entering different numbers in the input fields. The calculator will compute the binomial probability based on your inputs.

What is the difference between binomial probability and normal distribution?

Binomial probability is used for discrete events with a fixed number of trials and a constant probability of success, while the normal distribution is used for continuous data. For large n and moderate p, binomial distributions can approximate normal distributions.