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Calculate Hydrogen Reacts with Excess Nitrogen As Follows

Reviewed by Calculator Editorial Team

This guide explains how to calculate the reaction between hydrogen gas (H₂) and excess nitrogen gas (N₂) using stoichiometry principles. We'll cover the balanced chemical equation, stoichiometric calculations, and practical applications.

Introduction

The reaction between hydrogen and nitrogen is a fundamental chemical process with important industrial applications. When hydrogen reacts with excess nitrogen, the primary product is ammonia (NH₃), which is used in fertilizers, explosives, and other chemical industries.

Understanding this reaction requires knowledge of stoichiometry, which allows us to predict the quantities of reactants and products based on the balanced chemical equation.

Balanced Chemical Equation

The balanced chemical equation for the reaction between hydrogen and nitrogen is:

N₂ + 3H₂ → 2NH₃

This equation shows that:

  • 1 mole of nitrogen (N₂) reacts with 3 moles of hydrogen (H₂)
  • This produces 2 moles of ammonia (NH₃)

The equation is balanced because the number of atoms for each element is the same on both sides of the equation.

Stoichiometry Calculations

Stoichiometry allows us to calculate the quantities of reactants and products in a chemical reaction. For the hydrogen-nitrogen reaction, we can use the balanced equation to determine:

  • How much hydrogen is needed to react with a given amount of nitrogen
  • How much ammonia will be produced
  • How much nitrogen will remain unreacted when there's excess hydrogen

The key stoichiometric relationships are:

Moles of H₂ needed = 3 × Moles of N₂ reacted

Moles of NH₃ produced = 2 × Moles of N₂ reacted

When nitrogen is in excess, the amount of ammonia produced is determined by the limiting reactant (hydrogen in this case).

Worked Example

Let's calculate the reaction when 2 moles of nitrogen react with excess hydrogen:

  1. Calculate the moles of hydrogen needed: 3 × 2 = 6 moles of H₂
  2. Calculate the moles of ammonia produced: 2 × 2 = 4 moles of NH₃
  3. Since we have excess nitrogen, all 6 moles of hydrogen will react completely

In this scenario, 4 moles of ammonia are produced, and 2 moles of nitrogen remain unreacted.

Practical Applications

The hydrogen-nitrogen reaction has several important industrial applications:

  • Production of ammonia for fertilizers
  • Manufacture of nitric acid and other nitrogen compounds
  • Haber-Bosch process for ammonia synthesis
  • Production of hydrazine for rocket fuel

Understanding the stoichiometry of this reaction is essential for optimizing industrial processes and ensuring product quality.

FAQ

What is the balanced equation for hydrogen and nitrogen reaction?
The balanced equation is N₂ + 3H₂ → 2NH₃, showing that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.
How do you calculate the amount of ammonia produced?
Multiply the moles of nitrogen reacted by 2 (from the balanced equation) to get the moles of ammonia produced.
What happens when nitrogen is in excess?
When nitrogen is in excess, the amount of ammonia produced is determined by the limiting reactant (hydrogen), and some nitrogen will remain unreacted.
What are the industrial uses of this reaction?
The reaction is used in the production of ammonia for fertilizers, nitric acid, and other nitrogen compounds, as well as for hydrazine production.
What factors affect the reaction rate?
Factors include temperature, pressure, catalyst presence, and surface area of reactants, though stoichiometry remains constant regardless of these factors.