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Calculate for Unknown X 2 X 200 0.5 230

Reviewed by Calculator Editorial Team

This guide explains how to solve for the unknown variable x in the equation 2x + 200 = 0.5x + 230. We'll cover the step-by-step process, provide a worked example, and include an interactive calculator to verify your results.

How to Solve for Unknown x

Solving for x in a linear equation involves isolating the variable on one side of the equation. Here's the general approach:

  1. Start with the equation: 2x + 200 = 0.5x + 230
  2. Subtract 0.5x from both sides to get all x terms on one side
  3. Subtract 200 from both sides to isolate the constant terms
  4. Divide both sides by the coefficient of x to solve for x

Formula Used

The general solution for equations of the form ax + b = cx + d is:

x = (d - b) / (a - c)

Step-by-Step Solution

Let's solve the equation 2x + 200 = 0.5x + 230 step by step:

  1. Subtract 0.5x from both sides:

    2x - 0.5x + 200 = 230

    1.5x + 200 = 230

  2. Subtract 200 from both sides:

    1.5x = 230 - 200

    1.5x = 30

  3. Divide both sides by 1.5:

    x = 30 / 1.5

    x = 20

Important Note

When solving equations, always perform the same operation on both sides to maintain equality. This ensures the solution remains valid.

Worked Example

Let's verify our solution with a different set of numbers. Suppose we have the equation 3x + 150 = 1.5x + 180.

  1. Subtract 1.5x from both sides:

    3x - 1.5x + 150 = 180

    1.5x + 150 = 180

  2. Subtract 150 from both sides:

    1.5x = 180 - 150

    1.5x = 30

  3. Divide both sides by 1.5:

    x = 30 / 1.5

    x = 20

In both cases, we arrive at x = 20, demonstrating the consistency of the solution method.

Frequently Asked Questions

What if the coefficients of x are the same on both sides?
If the coefficients are identical, the equation will simplify to a statement about constants. For example, 2x + 5 = 2x + 10 simplifies to 5 = 10, which is false, meaning there's no solution.
Can I solve for x if the equation has decimals?
Yes, you can solve for x with decimal coefficients. The process remains the same: isolate the x terms and constants, then divide by the coefficient of x.
What if the equation has negative coefficients?
Negative coefficients work the same way as positive ones. Just be careful with the signs when subtracting terms. For example, in -2x + 10 = -x + 5, you would add x to both sides first.
How do I know if my solution is correct?
Substitute your solution back into the original equation to verify. If both sides equal the same value, your solution is correct.