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Calculate Energy 488.0 Nm Wavelength of Argon Laser

Reviewed by Calculator Editorial Team

An argon laser with a wavelength of 488.0 nm emits photons with specific energy levels. This calculator determines the energy of these photons using Planck's equation, which relates photon energy to wavelength.

Introduction

Argon lasers are widely used in scientific research, medical procedures, and industrial applications due to their precise wavelength output. The 488.0 nm wavelength is particularly significant because it falls within the visible light spectrum, making it useful for applications like fluorescence microscopy and laser surgery.

The energy of photons emitted by a laser can be calculated using Planck's equation, which shows the relationship between photon energy and wavelength. Understanding this energy is crucial for determining the laser's effectiveness and safety in various applications.

Formula

The energy (E) of a photon can be calculated using Planck's equation:

E = h × c / λ

Where:

  • E = Energy of the photon (in joules, J)
  • h = Planck's constant (6.62607015 × 10-34 J·s)
  • c = Speed of light in a vacuum (299,792,458 m/s)
  • λ = Wavelength of the photon (in meters, m)

For the 488.0 nm wavelength, we first convert the wavelength from nanometers to meters:

λ = 488.0 nm = 488.0 × 10-9 m

How to Use the Calculator

  1. The calculator automatically uses the fixed wavelength of 488.0 nm.
  2. Click the "Calculate" button to compute the photon energy.
  3. The result will be displayed in joules and electron volts.
  4. Use the "Reset" button to clear the calculation.

Note: The calculator uses Planck's constant and the speed of light as defined by the International System of Units (SI).

Example Calculation

Let's calculate the energy of a photon with a wavelength of 488.0 nm:

  1. Convert the wavelength to meters: 488.0 nm = 4.880 × 10-7 m
  2. Plug the values into Planck's equation:

    E = (6.62607015 × 10-34 J·s) × (299,792,458 m/s) / (4.880 × 10-7 m)

  3. Calculate the energy:

    E ≈ 4.09 × 10-19 J

  4. Convert the energy to electron volts (eV):

    1 eV = 1.602176634 × 10-19 J

    E ≈ 4.09 × 10-19 J / 1.602176634 × 10-19 J ≈ 2.55 eV

The energy of a photon with a wavelength of 488.0 nm is approximately 2.55 electron volts.

Applications

Argon lasers with a 488.0 nm wavelength are used in various fields:

  • Medical Field: Used in laser surgery and dermatology for precise tissue removal.
  • Scientific Research: Employed in fluorescence microscopy to study biological samples.
  • Industrial Applications: Used in material processing and engraving.
Common Applications of 488.0 nm Argon Lasers
Application Description
Laser Surgery Precise removal of tissue with minimal damage to surrounding areas.
Fluorescence Microscopy Visualization of biological samples with high resolution.
Material Processing Cutting and engraving of various materials.

FAQ

What is the energy of a photon with a wavelength of 488.0 nm?

The energy of a photon with a wavelength of 488.0 nm is approximately 2.55 electron volts, which is calculated using Planck's equation.

Why is the 488.0 nm wavelength significant?

The 488.0 nm wavelength falls within the visible light spectrum, making it useful for applications like fluorescence microscopy and laser surgery.

How is the energy of a photon calculated?

The energy of a photon is calculated using Planck's equation, which relates photon energy to wavelength.