Basic Calculator II LeetCode Problem Solver
An expert tool to compute string expressions according to the rules of the LeetCode problem 227, “Basic Calculator II”. This calculator correctly handles operator precedence (*, / before +, -) and integer division.
Enter a valid string containing non-negative integers and operators (+, -, *, /). Whitespace is ignored.
What is the basic calculator 2 leetcode Problem?
The “Basic Calculator II” problem, found on platforms like LeetCode as problem #227, is a classic computer science challenge. It asks you to implement a calculator that evaluates a simple mathematical expression given as a string. This is not a typical finance or health calculator; it’s an abstract math problem focused on algorithms and data structures.
The expression string contains only non-negative integers and the four basic operators: addition (+), subtraction (-), multiplication (*), and division (/). A key requirement is to respect standard operator precedence, meaning multiplication and division are performed before addition and subtraction. Another crucial rule is that integer division should truncate toward zero (e.g., 3 / 2 results in 1). This tool is designed for software developers, computer science students, and interview candidates who are learning about or practicing string parsing, stack utilization, and algorithm design. See our algorithm complexity calculator for more.
The “Basic Calculator II” Algorithm and Formula
There isn’t a single “formula” for the basic calculator 2 leetcode problem, but rather a well-defined algorithm. The most common and efficient approach uses a stack data structure to handle the operator precedence without building a full expression tree. The algorithm iterates through the expression string once, keeping track of the last seen operator and the current number being parsed.
Algorithm Steps:
- Initialize an empty stack, a
currentNumbervariable to 0, and alastOperatorvariable to ‘+’. - Iterate through the string character by character.
- If the character is a digit, build the
currentNumber(e.g., if you see ‘1’ then ‘2’, the number is 12). - If the character is an operator (or you reach the end of the string), process the
currentNumberbased on thelastOperator:- If
lastOperatorwas+, pushcurrentNumberonto the stack. - If
lastOperatorwas-, push-currentNumberonto the stack. - If
lastOperatorwas*, pop the top element from the stack, multiply it bycurrentNumber, and push the result back. - If
lastOperatorwas/, pop the top element, divide it bycurrentNumber(integer division), and push the result back.
- If
- After processing, update
lastOperatorto the current operator and resetcurrentNumberto 0. - Once the entire string is processed, the final result is the sum of all numbers in the stack.
Variables Table
| Variable | Meaning | Unit | Typical Range |
|---|---|---|---|
s |
The input expression string. | String | 1 to 3 * 10^5 characters |
stack |
A data structure to store intermediate values after applying * and /. | Array of Integers | Unitless numbers |
currentNumber |
The integer being parsed from digits. | Integer | Non-negative integers |
lastOperator |
The operator preceding the currentNumber. |
Character | +, -, *, / |
Practical Examples
Example 1: “3 + 2 * 2”
- Input String: “3 + 2 * 2”
- Process:
- Sees
3,lastOperatoris+. At the+, pushes3to stack. Stack:. - Sees
2,lastOperatoris+. At the*, pushes2to stack. Stack:. - Sees
2,lastOperatoris*. At the end, pops2, calculates2 * 2 = 4, pushes4. Stack:. - End of string. Sum stack:
3 + 4.
- Sees
- Result: 7
Example 2: ” 3 / 2 “
- Input String: ” 3 / 2 “
- Process:
- Sees
3,lastOperatoris+. At the/, pushes3to stack. Stack:. - Sees
2,lastOperatoris/. At the end, pops3, calculates3 / 2 = 1(integer division), pushes1. Stack:. - End of string. Sum stack.
- Sees
- Result: 1
Understanding these examples is key to mastering the algorithm. You can learn more with our binary search visualization.
How to Use This Basic Calculator II Calculator
Using this tool is straightforward and designed to help you quickly test expressions for the basic calculator 2 leetcode problem.
- Enter the Expression: Type your mathematical expression into the “Enter Mathematical Expression” input field. The expression must only contain numbers,
+,-,*,/, and spaces. - Calculate: Click the “Calculate” button.
- Interpret the Result: The final integer result will appear in the blue box below. The calculator automatically handles operator precedence and integer division, just as required by the problem statement.
- Reset: Click the “Reset” button to clear the input field and the result.
Key Factors That Affect the Calculation
- Operator Precedence: The most critical factor. Multiplication (
*) and division (/) have higher precedence than addition (+) and subtraction (-). This logic is built into the calculator. - Integer Division: The problem specifies that division between two integers should truncate toward zero.
5 / 2is2, and-5 / 2is-2. - No Parentheses: This version of the problem does not involve parentheses. Handling parentheses requires a more complex algorithm, often involving recursion or two stacks (see the “Basic Calculator I” or “III” problems).
- Whitespace: Spaces in the expression are ignored and do not affect the result.
"3+2*2"is the same as" 3 + 2 * 2 ". - Order of Operations (Left-to-Right): For operators of the same precedence (e.g., a string of `*` and `/`), they are evaluated from left to right.
- Valid Input Assumption: The underlying algorithm assumes the input string is always a valid mathematical expression. Invalid inputs (like
"3 + * 2") will lead to an error. Our string similarity calculator can help analyze different expressions.
Frequently Asked Questions (FAQ)
- 1. Why not just use JavaScript’s `eval()` function?
- While `eval()` can compute a string expression, it’s forbidden in the context of the LeetCode problem. The goal is to implement the parsing and evaluation logic yourself. Furthermore, `eval()` is a major security risk in production applications and does not perform integer division by default. This makes it an unsuitable solution for the problem’s constraints.
- 2. How does the calculator handle operator precedence?
- It uses a stack-based, single-pass algorithm. Instead of immediately performing addition or subtraction, it pushes the numbers (or their negative counterparts) onto a stack. When it encounters a multiplication or division, it immediately modifies the last number pushed onto the stack, thereby giving `*` and `/` precedence.
- 3. What happens if I enter an invalid expression?
- This calculator includes basic error checking and will display an “Invalid Expression” message if it encounters characters that are not digits, valid operators, or spaces, or if it detects division by zero.
- 4. How is integer division handled?
- The JavaScript code uses `Math.trunc(a / b)` to ensure division truncates toward zero, correctly handling both positive and negative results as per the problem’s requirements.
- 5. Can this calculator handle parentheses?
- No. This calculator is specifically for the “Basic Calculator II” problem, which does not include parentheses. Problems like “Basic Calculator” (I) or “Basic Calculator III” on LeetCode introduce parentheses and require a more complex, recursive, or multi-stack algorithm.
- 6. Does the order matter for multiple multiplications or divisions?
- Yes. Operators with the same precedence are evaluated from left to right. For example,
10 / 2 * 5is calculated as(10 / 2) * 5 = 25. The algorithm correctly handles this. You might find our permutation and combination calculator interesting for exploring orderings. - 7. What is the time complexity of this algorithm?
- The algorithm iterates through the input string once. This gives it a time complexity of O(n), where n is the length of the string. The space complexity is also O(n) in the worst case, as the stack could potentially store all the numbers in the expression (e.g., “1+2+3+4+5”).
- 8. Why are the values unitless?
- This is an abstract math problem. The numbers in the expression do not represent physical quantities like meters or dollars; they are pure, unitless integers. Therefore, units are not relevant to the calculation.