Ax2 Bx C 0 Calculator
This calculator solves quadratic equations of the form ax² + bx + c = 0. Whether you're a student studying algebra or an engineer working with physics problems, this tool provides quick and accurate solutions to quadratic equations.
How to Use This Calculator
Using our quadratic equation solver is simple:
- Enter the coefficients a, b, and c in the input fields provided.
- Click the "Calculate" button to solve the equation.
- View the results, which include the roots of the equation and a graphical representation.
- Use the "Reset" button to clear the inputs and start over.
The calculator will display the roots of the equation and provide additional information about the nature of the roots based on the discriminant.
The Quadratic Formula
The quadratic formula is the standard method for solving quadratic equations. The formula is:
x = [-b ± √(b² - 4ac)] / (2a)
Where:
- a, b, and c are coefficients of the quadratic equation
- x represents the roots of the equation
- √(b² - 4ac) is the discriminant
The quadratic formula provides two solutions for x, which are the roots of the quadratic equation. These roots can be real and distinct, real and equal, or complex conjugates depending on the value of the discriminant.
Understanding the Discriminant
The discriminant (b² - 4ac) determines the nature of the roots of a quadratic equation:
- If the discriminant is positive, there are two distinct real roots.
- If the discriminant is zero, there is exactly one real root (a repeated root).
- If the discriminant is negative, there are two complex conjugate roots.
The calculator will analyze the discriminant and provide information about the nature of the roots in the results section.
Worked Examples
Example 1: Two Distinct Real Roots
Solve x² - 5x + 6 = 0.
Using the quadratic formula:
x = [5 ± √(25 - 24)] / 2 = [5 ± 1] / 2
This gives two solutions: x = 3 and x = 2.
Example 2: One Real Root
Solve x² - 6x + 9 = 0.
Using the quadratic formula:
x = [6 ± √(36 - 36)] / 2 = 6 / 2 = 3
This gives one real root: x = 3.
Example 3: Complex Roots
Solve x² + 2x + 5 = 0.
Using the quadratic formula:
x = [-2 ± √(4 - 20)] / 2 = [-2 ± √(-16)] / 2 = [-2 ± 4i] / 2
This gives two complex solutions: x = -1 + 2i and x = -1 - 2i.