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1x 2y 15.95 3x 5y 45.90 Algebra Calculator

Reviewed by Calculator Editorial Team

This calculator solves the system of linear equations: 1x + 2y = 15.95 and 3x + 5y = 45.90. It provides the values of x and y that satisfy both equations simultaneously.

How to Use This Calculator

To solve the system of equations:

  1. Enter the coefficients for x and y in the first equation (1x + 2y = 15.95)
  2. Enter the coefficients for x and y in the second equation (3x + 5y = 45.90)
  3. Click "Calculate" to find the solution
  4. Review the results and interpretation

Note: This calculator assumes the system has exactly one solution. If the equations are dependent or inconsistent, the calculator will indicate this.

Formula Explained

For a system of equations:

a₁x + b₁y = c₁

a₂x + b₂y = c₂

The solution can be found using the following formulas:

x = (b₂c₁ - b₁c₂) / (a₁b₂ - a₂b₁)

y = (a₁c₂ - a₂c₁) / (a₁b₂ - a₂b₁)

For our specific equations:

1x + 2y = 15.95

3x + 5y = 45.90

The determinant (a₁b₂ - a₂b₁) is calculated as (1×5 - 3×2) = (5 - 6) = -1.

Worked Example

Let's solve the system:

1x + 2y = 15.95

3x + 5y = 45.90

  1. Calculate the determinant: (1×5 - 3×2) = -1
  2. Calculate x: (5×15.95 - 2×45.90) / -1 = (79.75 - 91.80) / -1 = (-12.05) / -1 = 12.05
  3. Calculate y: (1×45.90 - 3×15.95) / -1 = (45.90 - 47.85) / -1 = (-1.95) / -1 = 1.95

The solution is x = 12.05 and y = 1.95.

Interpreting Results

The calculator provides two values:

  • x value: The solution for x that satisfies both equations
  • y value: The solution for y that satisfies both equations

If the determinant is zero, the system either has infinitely many solutions (dependent equations) or no solution (inconsistent equations).

Tip: Always verify your results by plugging the values back into the original equations.

Frequently Asked Questions

What if the determinant is zero?
The system either has infinitely many solutions (dependent equations) or no solution (inconsistent equations).
Can this calculator solve systems with more than two variables?
No, this calculator is designed specifically for two-variable systems.
How accurate are the results?
The calculator uses standard algebraic methods and provides precise decimal solutions.
What if I enter non-linear equations?
This calculator is designed for linear equations only. Non-linear systems require different methods.
Can I use this calculator for real-world problems?
Yes, the solutions can be applied to any real-world scenario involving two variables and two linear equations.