1x 2y 15.95 3x 5y 45.90 Algebra Calculator
This calculator solves the system of linear equations: 1x + 2y = 15.95 and 3x + 5y = 45.90. It provides the values of x and y that satisfy both equations simultaneously.
How to Use This Calculator
To solve the system of equations:
- Enter the coefficients for x and y in the first equation (1x + 2y = 15.95)
- Enter the coefficients for x and y in the second equation (3x + 5y = 45.90)
- Click "Calculate" to find the solution
- Review the results and interpretation
Note: This calculator assumes the system has exactly one solution. If the equations are dependent or inconsistent, the calculator will indicate this.
Formula Explained
For a system of equations:
a₁x + b₁y = c₁
a₂x + b₂y = c₂
The solution can be found using the following formulas:
x = (b₂c₁ - b₁c₂) / (a₁b₂ - a₂b₁)
y = (a₁c₂ - a₂c₁) / (a₁b₂ - a₂b₁)
For our specific equations:
1x + 2y = 15.95
3x + 5y = 45.90
The determinant (a₁b₂ - a₂b₁) is calculated as (1×5 - 3×2) = (5 - 6) = -1.
Worked Example
Let's solve the system:
1x + 2y = 15.95
3x + 5y = 45.90
- Calculate the determinant: (1×5 - 3×2) = -1
- Calculate x: (5×15.95 - 2×45.90) / -1 = (79.75 - 91.80) / -1 = (-12.05) / -1 = 12.05
- Calculate y: (1×45.90 - 3×15.95) / -1 = (45.90 - 47.85) / -1 = (-1.95) / -1 = 1.95
The solution is x = 12.05 and y = 1.95.
Interpreting Results
The calculator provides two values:
- x value: The solution for x that satisfies both equations
- y value: The solution for y that satisfies both equations
If the determinant is zero, the system either has infinitely many solutions (dependent equations) or no solution (inconsistent equations).
Tip: Always verify your results by plugging the values back into the original equations.
Frequently Asked Questions
- What if the determinant is zero?
- The system either has infinitely many solutions (dependent equations) or no solution (inconsistent equations).
- Can this calculator solve systems with more than two variables?
- No, this calculator is designed specifically for two-variable systems.
- How accurate are the results?
- The calculator uses standard algebraic methods and provides precise decimal solutions.
- What if I enter non-linear equations?
- This calculator is designed for linear equations only. Non-linear systems require different methods.
- Can I use this calculator for real-world problems?
- Yes, the solutions can be applied to any real-world scenario involving two variables and two linear equations.